# What is the electric field magnitude in the velocity selector_

• It is an equation for the electric field produced by the point charge. 6 . Do not use E = kQ /r 2 here because the electric field is known. So, the source of the electric field is irrelevant—just use F = qE to find that the force on the charge is (1 C)(100 N/C) = 100 N.
• Aug 27, 2009 · [/caption] The charge of the electron is equivalent to the magnitude of the elementary charge (e) but bearing a negative sign. Since the value of the elementary charge is roughly 1.602 x 10-19 ...
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• It’s also worth noting that the magnitude of v is always less than the magnitude of the unit vector u (because we have taken units of space and time such that c = 1), so the sign of the electric field (with a = 0) is always positive for any velocity v, positive or negative.
• Feb 16, 2016 · A velocity selector having uniform perpendicular electric and magnetic fields is shown in the figure (Figure 1) . The electric field is provided by a 150V DC battery connected across two large parallel metal plates that are 4.50cm apart. Part A. What must be the magnitude of the magnetic field so...
• Imposing an electric field on a conductor gives rise to a current which in turn generates a magnetic field. One could then inquire whether or not an electric field could be produced by a magnetic field. In 1831, Michael Faraday discovered that, by varying magnetic field with time, an electric field could be generated.
• The electric field strength, E, at a point in the field is defined as the force per unit charge on a positive test charge placed at that point. The unit of E is the newton per coulomb (NC^-1). If a positive test charge Q at a certain point in an electric field is acted on by force F due to the electric field, the electric field strength, E, at ...
• A velocity selector uses a 64mT magnetic field perpendicular to a 28kN/C electric field. At what speed will charged particles pass through the selector undeflected?
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• The velocity of the electron (it is moving so fast!) If the velocity is perpendicular the magnetic field, the radius of the circular motion ( it is so small!) If the velocity has a small component along the magnetic (say 1%), The electron will move along the magnetic field line with velocity Image how the electron moves under the above conditions!
• An electron is projected with velocity v 0 in a uniform electric field E perpendicular to the field. Again it is projected with velocity v 0 perpendicular to a uniform magnetic field B . If r 1 is initial radius of curvature just after entering in the electric field and r 2 is initial radius of curvature just after entering in magnetic field ...
• Ions in the beam emerge from the velocity selector at a speed of 3.00 x 105 m/s and enter a uniform magnetic field of 0.600 T directed perpendicularly to the velocity of the ions. Q : Problem related to magnitude of the vehicles velocity
• The direction of the electric field at any point in space is the direction of the net electric force on a "small" positive test charge. Use vector addition to find the net electric field when more than one charged object is present. Diagrams The electric field around a spherically symmetric charge is radial and… diverges from positive charge
• Feb 13, 2019 · A velocity selector is built with a magnetic field of magnitude 5.2 T and an electric field of strength 4.6 × 10 ^4 N/C. The directions of the two fields are perpendicular to each other. At what speed will electrons pass through the selector without deflection? Let the charge of an electron q = −1.6 × 10 ^ −19 A.8.8 × 10^3 m/s B 2.4 × 10 ^ - 15 m/s C 7.9 × 10 ^ 13 m/s D 2.0 x 10 ^ 4 m/s
• 21.3 The Motion of a Charged Particle in a Magnetic Field Example: Velocity Selector A velocity selector is a device for measuring the velocity of a charged particle. The device operates by applying electric and magnetic forces to the particle in such a way that these forces balance. Given B and q, wow should an electric field be
• The electric field between the plates of the velocity selector is 950 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.930 T. Calculate the radius of the path in the system for a singly charged ion with mass m = 2.18 × 10–26 kg.
• The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field. Knowledge of the value of the electric field at a point, without any specific knowledge of what produced the field, is all that is needed to determine what will happen to electric charges close to that particular point.
• Accelerating electrons in a constant E-field A single electron is accelerated from rest in a constant electric field of 1000 N/C through a distance of 3 cm. Find the electric force on the electron, and calculate its final velocity (m e = 9.1x10-31 kg) E F = qE = m ea F = qE = (1.6x10–19 C)(1000N/C) - = 1.6x10–16 N
• Charged particles pass through a velocity selector with electric and magnetic fields at right angles to each other, as shown in FIGURE $22-42$ . If the electric field has a magnitude of 450 $\mathrm{N} / \mathrm{C}$ and the magnetic field has a magnitude of 0.18 $\mathrm{T}$ , what speed must the par-
Club car golf cart parts11. A particle with a mass m = 2.0 x 10-12 kg velocity v = 10 6 m/s and charge q = 10-6 C enters region 1 between the parallel plates where there is an electric field E = 10 6 N/C. Find (a) the direction and magnitude of the magnetic field B perpendicular to the velocity of the particle in Region 1 that allows the particle to pass through Region 1 without a deflection, (b) the direction of the ... The solution procedure iteratively computes electric body and surface forces and then includes those into the Navier-Stokes equation to predict the velocity field and other fluid parameters.
Oct 22, 2020 · The magnitude of this induced EMF depends upon the rate of change of flux (magnetic line force) linkage with the conductor. This EMF will cause a current to flow if the conductor circuit is closed. Hence the most basic two essential parts of a generator are: The magnetic field; Conductors which move inside that magnetic field.
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• Electric Field & Magnetic Field q Electric forces acting at a distance through electric field. q Vector field, E. q Source: electric charge. q Positive charge (+) and negative charge (-). q Opposite charges attract, like charges repel. q Electric field lines visualizing the direction and magnitude of E. q Magnetic forces acting at a The electric field is a physical object which can carry both momentum and energy. It is the mediator (or carrier) of the electric force. The electric field is massless. The Electric Field is a Vector Field : r E KQ r = 2 r\$
• Magnitude of the Electric Field E A collection of charges at rest in space will exert a force of magnitude F on any charge q placed at any point in that space. The ratio F/q is defined to be the magnitude of the electric field E at that point, measured in newtons/coulomb (N/C).
• A velocity selector consists of electric and magnetic fields described by the expressions E = Ek and B = Bj, with B = 15.0 mT. Find the value of E such that a 750-eV electron moving along the positive x axis is undeflected.

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The electric field generated by a static charge or a constant current always has zero loop integral. A constant current is a continuous line of evenly-spaced charges moving with constant velocity. An electric field generated by any other configuration of moving charges (moving through the loop) would have a non-zero loop integral.
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Magnetic Force Formula (Charge-Velocity) Questions: 1) A beam of protons, each with charge , is moving at through a uniform magnetic field with magnitude 0.60T. The direction of motion of the protons is to the right of the page (screen), and the magnetic field direction is downward-right, at an angle of from the proton direction.
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The direction of an electrical field at a point is the same as the direction of the electrical force acting on a positive test charge at that point. For example, if you place a positive test charge in an electric field and the charge moves to the right, you know the direction of the electric field in that region points to the right.
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A velocity selector uses a fixed electric field of magnitude E and the magnetic field is varied to select particles of various energies. If the electric field strength s 9.6 x 101 N/C, what should be the value of the magnetic field (in tesla) to select protons of velocity 8.7 x 10° m/s 0.1100 orrectAnswer) 0.0906 margin of error +/-396.
• (a) What is the electric-field magnitude in the velocity selector? V/m (b) If the separation of the plates is 4.90 mm, what is the potential difference between plates {eq}P {/eq} and {eq}P' {/eq}? kV
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• The electric field Intensity at a point is the force experienced by a unit positive charge placed at that point. Electric Field Intensity is a vector quantity. It is denoted by ‘E’. Formula: Electric Field = F/q. Unit of E is NC-1 or Vm-1. The electric field intensity due to a positive charge is always directed away from the charge and the ... The magnetic potential energy of a magnetic dipole in a magnetic field is October 31, 2007 Center for Solar-Terrestrial Research Physics 121: Electricity & Magnetism – Lecture 9 Magnetic Fields Dale E. Gary Wenda Cao NJIT Physics Department Electric Field & Magnetic Field Electric forces acting at a distance through electric field.
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• The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field. Knowledge of the value of the electric field at a point, without any specific knowledge of what produced the field, is all that is needed to determine what will happen to electric charges close to that particular point.
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• It's saying that the absolute value, or the magnitude of the electric field created at a point in space is equal to k, the electric constant, times the charge creating the field. This is important. This charge, Q1, is creating this electric field.
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• A velocity selector is a region in which there is a uniform electric field and a uniform magnetic field. The fields are perpendicular to one another, and perpendicular to the initial velocity of the charged particles that are passing through the region. The force exerted on a charged particle by the electric field is given by: F = qE. The magnitude of the force exerted by the magnetic field is F = qvB, as long as the velocity is perpendicular to the field.
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